Voltage loss in a wire is synonymous to pressure loss in a pipe. Electric current flows in a wire, just like water in a pipe, and creates a loss. The loss is a function of:
Voltage Loss is calculated using "OHM'S LAW", as follows:
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E = IR |
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| Where: | E is the Voltage Loss, in volts | ||
| I is the current flowing through the wire, in amperes | |||
| R is the resistance of the wire, in ohms |
For single-phase circuits, the formula for Voltage Loss is:
For three-phase circuits, the formula for Voltage Loss is:
Example:
A controller in a city park will be installed 4,200 feet away (this is the total trench length) from the 115 VAC power source. What is the voltage loss using 14 AWG wire? Is this size wire large enough?
| 1. | From the catalog of the controller manufacturer we find that the controller will consume 0.25 amperes when two valves are activated. |
| 2. | From the chart below, the resistance for 14 AWG wire is 2.525 ohms/thousand feet. |
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COPPER WIRE RESISTANCE (OHMS PER 1000' OF WIRE) |
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WIRE GAUGE (AWG) |
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| 18 | 16 | 14 | 14/12 | 14/10 | 12 | 10 | 8 | 6 | 4 | 2 | 1/0 | 2/0 |
| 6.385 | 4.016 | 2.525 | 2.057 | 1.762 | 1.588 | .999 | .628 | .395 | .249 | .156 | .098 | .078 |
| 3. | From the formula for single-phase circuits: |
| Voltage Loss = Amps X Wire Resistance per 1,000 feet X Distance in thousands of feet X 2 Wires | |
| Voltage Loss = 0.25 amps X 2.525 ohms/MFT X 4.2 MFT X 2 Wires | |
| Voltage Loss = 5.3025 or approximately 5.3 volts | |
| 4. | To determine if this is acceptable, we subtract the 5.3 volt loss form the 115 VAC at the source. The voltage at the controller is 115 - 5.3 = 109.7 volts. This is within the controller manufacturer's requirements of 105 - 120 volts, and is therefore acceptable. |
The same formula can be used to try other sizes of wire.
If you need help, please check with your closest Paige Electric representative.